A time insurance company determines; average it receive 4 extermination claims-a-day. Probability at least possible 7 ensue?
A small life insurance company determines; on average it receives 4 release claims per day. Find Probability of receiving at tiniest 7 on a randomly selected daylight.
Answers:
The answer could ebb and flow by person.It is alway a good notion to hear the suggestion from different sides and try to choose the best one.Here is a good one i recommend.
The average alone is not adequate information for me to provide you with an answer. Answerer (1) either assumed some distribution and standard deviation or is purely messing with your head. Since I notice that he still has no "best answers" and only 12 answers including his answer to you, I suspect that he is only messing with your head. Unfortunately that happen a lot on InsuranceQuotesFAQ.com.
There must be some sort of definition of the distribution and at least an added piece of information. It could be a normal distribution with a standard deviation of 1, it could be a average distribution with a standard deviation of 2, it could be a binomial distribution with a standard deviation of .5, and so on. There are infinitely masses possibilities.
Even if I were to assume that the distribution was conventional, I would still need the standard deviation. If I had that later I could look into a book of distribution tables and provide you with your answer.
0.111
I am assuming poisson distribution with mean 4.
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Answers:
The answer could ebb and flow by person.It is alway a good notion to hear the suggestion from different sides and try to choose the best one.Here is a good one i recommend.
The average alone is not adequate information for me to provide you with an answer. Answerer (1) either assumed some distribution and standard deviation or is purely messing with your head. Since I notice that he still has no "best answers" and only 12 answers including his answer to you, I suspect that he is only messing with your head. Unfortunately that happen a lot on InsuranceQuotesFAQ.com.
There must be some sort of definition of the distribution and at least an added piece of information. It could be a normal distribution with a standard deviation of 1, it could be a average distribution with a standard deviation of 2, it could be a binomial distribution with a standard deviation of .5, and so on. There are infinitely masses possibilities.
Even if I were to assume that the distribution was conventional, I would still need the standard deviation. If I had that later I could look into a book of distribution tables and provide you with your answer.
0.111
I am assuming poisson distribution with mean 4.
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